Optimal. Leaf size=202 \[ -\frac{b \left (24 a^2+35 b^2\right ) \sin (c+d x)}{8 d}-\frac{(a+b) \left (8 a^2+37 a b+35 b^2\right ) \log (1-\sin (c+d x))}{16 d}-\frac{(a-b) \left (8 a^2-37 a b+35 b^2\right ) \log (\sin (c+d x)+1)}{16 d}-\frac{3 a b^2 \sin ^2(c+d x)}{2 d}+\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}-\frac{b^3 \sin ^3(c+d x)}{3 d} \]
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Rubi [A] time = 0.34084, antiderivative size = 202, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 5, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.238, Rules used = {2721, 1645, 1629, 633, 31} \[ -\frac{b \left (24 a^2+35 b^2\right ) \sin (c+d x)}{8 d}-\frac{(a+b) \left (8 a^2+37 a b+35 b^2\right ) \log (1-\sin (c+d x))}{16 d}-\frac{(a-b) \left (8 a^2-37 a b+35 b^2\right ) \log (\sin (c+d x)+1)}{16 d}-\frac{3 a b^2 \sin ^2(c+d x)}{2 d}+\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}-\frac{b^3 \sin ^3(c+d x)}{3 d} \]
Antiderivative was successfully verified.
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Rule 2721
Rule 1645
Rule 1629
Rule 633
Rule 31
Rubi steps
\begin{align*} \int (a+b \sin (c+d x))^3 \tan ^5(c+d x) \, dx &=\frac{\operatorname{Subst}\left (\int \frac{x^5 (a+x)^3}{\left (b^2-x^2\right )^3} \, dx,x,b \sin (c+d x)\right )}{d}\\ &=\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}+\frac{\operatorname{Subst}\left (\int \frac{(a+x)^2 \left (-3 b^6-4 a b^4 x-4 b^4 x^2-4 a b^2 x^3-4 b^2 x^4\right )}{\left (b^2-x^2\right )^2} \, dx,x,b \sin (c+d x)\right )}{4 b^2 d}\\ &=\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}+\frac{\operatorname{Subst}\left (\int \frac{(a+x) \left (21 a b^6+b^4 \left (8 a^2+27 b^2\right ) x+16 a b^4 x^2+8 b^4 x^3\right )}{b^2-x^2} \, dx,x,b \sin (c+d x)\right )}{8 b^4 d}\\ &=\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}+\frac{\operatorname{Subst}\left (\int \left (-24 a^2 b^4-35 b^6-24 a b^4 x-8 b^4 x^2+\frac{5 b^6 \left (9 a^2+7 b^2\right )+8 a b^4 \left (a^2+9 b^2\right ) x}{b^2-x^2}\right ) \, dx,x,b \sin (c+d x)\right )}{8 b^4 d}\\ &=-\frac{b \left (24 a^2+35 b^2\right ) \sin (c+d x)}{8 d}-\frac{3 a b^2 \sin ^2(c+d x)}{2 d}-\frac{b^3 \sin ^3(c+d x)}{3 d}+\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}+\frac{\operatorname{Subst}\left (\int \frac{5 b^6 \left (9 a^2+7 b^2\right )+8 a b^4 \left (a^2+9 b^2\right ) x}{b^2-x^2} \, dx,x,b \sin (c+d x)\right )}{8 b^4 d}\\ &=-\frac{b \left (24 a^2+35 b^2\right ) \sin (c+d x)}{8 d}-\frac{3 a b^2 \sin ^2(c+d x)}{2 d}-\frac{b^3 \sin ^3(c+d x)}{3 d}+\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}+\frac{\left ((a-b) \left (8 a^2-37 a b+35 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{-b-x} \, dx,x,b \sin (c+d x)\right )}{16 d}+\frac{\left ((a+b) \left (8 a^2+37 a b+35 b^2\right )\right ) \operatorname{Subst}\left (\int \frac{1}{b-x} \, dx,x,b \sin (c+d x)\right )}{16 d}\\ &=-\frac{(a+b) \left (8 a^2+37 a b+35 b^2\right ) \log (1-\sin (c+d x))}{16 d}-\frac{(a-b) \left (8 a^2-37 a b+35 b^2\right ) \log (1+\sin (c+d x))}{16 d}-\frac{b \left (24 a^2+35 b^2\right ) \sin (c+d x)}{8 d}-\frac{3 a b^2 \sin ^2(c+d x)}{2 d}-\frac{b^3 \sin ^3(c+d x)}{3 d}+\frac{\sec ^4(c+d x) (a+b \sin (c+d x))^3}{4 d}-\frac{\sec ^2(c+d x) (a+b \sin (c+d x))^2 (8 a+11 b \sin (c+d x))}{8 d}\\ \end{align*}
Mathematica [A] time = 1.0589, size = 199, normalized size = 0.99 \[ -\frac{144 b \left (a^2+b^2\right ) \sin (c+d x)+3 \left (8 a^2-37 a b+35 b^2\right ) (a-b) \log (\sin (c+d x)+1)+3 (a+b) \left (8 a^2+37 a b+35 b^2\right ) \log (1-\sin (c+d x))+72 a b^2 \sin ^2(c+d x)-\frac{3 (a-b)^3}{(\sin (c+d x)+1)^2}+\frac{3 (7 a-13 b) (a-b)^2}{\sin (c+d x)+1}-\frac{3 (a+b)^2 (7 a+13 b)}{\sin (c+d x)-1}-\frac{3 (a+b)^3}{(\sin (c+d x)-1)^2}+16 b^3 \sin ^3(c+d x)}{48 d} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.091, size = 420, normalized size = 2.1 \begin{align*}{\frac{{a}^{3} \left ( \tan \left ( dx+c \right ) \right ) ^{4}}{4\,d}}-{\frac{{a}^{3} \left ( \tan \left ( dx+c \right ) \right ) ^{2}}{2\,d}}-{\frac{{a}^{3}\ln \left ( \cos \left ( dx+c \right ) \right ) }{d}}+{\frac{3\,{a}^{2}b \left ( \sin \left ( dx+c \right ) \right ) ^{7}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{9\,{a}^{2}b \left ( \sin \left ( dx+c \right ) \right ) ^{7}}{8\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{9\,{a}^{2}b \left ( \sin \left ( dx+c \right ) \right ) ^{5}}{8\,d}}-{\frac{15\,{a}^{2}b \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{8\,d}}-{\frac{45\,{a}^{2}b\sin \left ( dx+c \right ) }{8\,d}}+{\frac{45\,{a}^{2}b\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}}+{\frac{3\,a{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{8}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{3\,a{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{8}}{2\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{3\,a{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{6}}{2\,d}}-{\frac{9\,a{b}^{2} \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{4\,d}}-{\frac{9\, \left ( \sin \left ( dx+c \right ) \right ) ^{2}a{b}^{2}}{2\,d}}-9\,{\frac{a{b}^{2}\ln \left ( \cos \left ( dx+c \right ) \right ) }{d}}+{\frac{{b}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{9}}{4\,d \left ( \cos \left ( dx+c \right ) \right ) ^{4}}}-{\frac{5\,{b}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{9}}{8\,d \left ( \cos \left ( dx+c \right ) \right ) ^{2}}}-{\frac{5\,{b}^{3} \left ( \sin \left ( dx+c \right ) \right ) ^{7}}{8\,d}}-{\frac{7\, \left ( \sin \left ( dx+c \right ) \right ) ^{5}{b}^{3}}{8\,d}}-{\frac{35\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}{b}^{3}}{24\,d}}-{\frac{35\,{b}^{3}\sin \left ( dx+c \right ) }{8\,d}}+{\frac{35\,{b}^{3}\ln \left ( \sec \left ( dx+c \right ) +\tan \left ( dx+c \right ) \right ) }{8\,d}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.00375, size = 293, normalized size = 1.45 \begin{align*} -\frac{16 \, b^{3} \sin \left (d x + c\right )^{3} + 72 \, a b^{2} \sin \left (d x + c\right )^{2} + 3 \,{\left (8 \, a^{3} - 45 \, a^{2} b + 72 \, a b^{2} - 35 \, b^{3}\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) + 3 \,{\left (8 \, a^{3} + 45 \, a^{2} b + 72 \, a b^{2} + 35 \, b^{3}\right )} \log \left (\sin \left (d x + c\right ) - 1\right ) + 144 \,{\left (a^{2} b + b^{3}\right )} \sin \left (d x + c\right ) - \frac{6 \,{\left ({\left (27 \, a^{2} b + 13 \, b^{3}\right )} \sin \left (d x + c\right )^{3} - 6 \, a^{3} - 30 \, a b^{2} + 4 \,{\left (2 \, a^{3} + 9 \, a b^{2}\right )} \sin \left (d x + c\right )^{2} -{\left (21 \, a^{2} b + 11 \, b^{3}\right )} \sin \left (d x + c\right )\right )}}{\sin \left (d x + c\right )^{4} - 2 \, \sin \left (d x + c\right )^{2} + 1}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.24481, size = 583, normalized size = 2.89 \begin{align*} \frac{72 \, a b^{2} \cos \left (d x + c\right )^{6} - 36 \, a b^{2} \cos \left (d x + c\right )^{4} - 3 \,{\left (8 \, a^{3} - 45 \, a^{2} b + 72 \, a b^{2} - 35 \, b^{3}\right )} \cos \left (d x + c\right )^{4} \log \left (\sin \left (d x + c\right ) + 1\right ) - 3 \,{\left (8 \, a^{3} + 45 \, a^{2} b + 72 \, a b^{2} + 35 \, b^{3}\right )} \cos \left (d x + c\right )^{4} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 12 \, a^{3} + 36 \, a b^{2} - 24 \,{\left (2 \, a^{3} + 9 \, a b^{2}\right )} \cos \left (d x + c\right )^{2} + 2 \,{\left (8 \, b^{3} \cos \left (d x + c\right )^{6} - 8 \,{\left (9 \, a^{2} b + 10 \, b^{3}\right )} \cos \left (d x + c\right )^{4} + 18 \, a^{2} b + 6 \, b^{3} - 3 \,{\left (27 \, a^{2} b + 13 \, b^{3}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{48 \, d \cos \left (d x + c\right )^{4}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.24366, size = 339, normalized size = 1.68 \begin{align*} -\frac{16 \, b^{3} \sin \left (d x + c\right )^{3} + 72 \, a b^{2} \sin \left (d x + c\right )^{2} + 144 \, a^{2} b \sin \left (d x + c\right ) + 144 \, b^{3} \sin \left (d x + c\right ) + 3 \,{\left (8 \, a^{3} - 45 \, a^{2} b + 72 \, a b^{2} - 35 \, b^{3}\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) + 3 \,{\left (8 \, a^{3} + 45 \, a^{2} b + 72 \, a b^{2} + 35 \, b^{3}\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) - \frac{6 \,{\left (6 \, a^{3} \sin \left (d x + c\right )^{4} + 54 \, a b^{2} \sin \left (d x + c\right )^{4} + 27 \, a^{2} b \sin \left (d x + c\right )^{3} + 13 \, b^{3} \sin \left (d x + c\right )^{3} - 4 \, a^{3} \sin \left (d x + c\right )^{2} - 72 \, a b^{2} \sin \left (d x + c\right )^{2} - 21 \, a^{2} b \sin \left (d x + c\right ) - 11 \, b^{3} \sin \left (d x + c\right ) + 24 \, a b^{2}\right )}}{{\left (\sin \left (d x + c\right )^{2} - 1\right )}^{2}}}{48 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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